Chef And Division Three(DIVTHREE)Solution — Codechef JanuaryLong Challenge

Problem Statement

Chef wants to host some Division-3 contests. Chef has N setters who are busy creating new problems for him. The ith setter has made Ai problems where 1≤i≤N.

A Division-3 contest should have exactly K problems. Chef wants to plan for the next D days using the problems that they have currently. But Chef cannot host more than one Division-3 contest in a day.

Given these constraints, can you help Chef find the maximum number of Division-3 contests that can be hosted in these D days?

Input:

• The first line of input contains a single integer T denoting the number of test cases. The description of T test cases follows.
• The first line of each test case contains three space-separated integers — N, K and D respectively.
• The second line of each test case contains N space-separated integers A1,A2,…,AN respectively.

Output:

For each test case, print a single line containing one integer ― the maximum number of Division-3 contests Chef can host in these D days.

Constraints

• 1≤T≤103
• 1≤N≤102
• 1≤K≤109
• 1≤D≤109
• 1≤Ai≤107 for each valid i

Subtasks

Subtask #1 (40 points):

• N=1
• 1≤A1≤105

Subtask #2 (60 points): Original constraints

Sample Input:

5
1 5 31
4
1 10 3
23
2 5 7
20 36
2 5 10
19 2
3 3 300
1 1 1

Sample Output:

0
2
7
4
1

Explanation:

• Example case 1: Chef only has A1=4A1=4 problems and he needs K=5K=5 problems for a Division-3 contest. So Chef won’t be able to host any Division-3 contest in these 31 days. Hence the first output is 00.
• Example case 2: Chef has A1=23A1=23 problems and he needs K=10K=10 problems for a Division-3 contest. Chef can choose any 10+10=2010+10=20 problems and host 22 Division-3 contests in these 3 days. Hence the second output is 22.
• Example case 3: Chef has A1=20A1=20 problems from setter-1 and A2=36A2=36 problems from setter-2, and so has a total of 5656 problems. Chef needs K=5K=5 problems for each Division-3 contest. Hence Chef can prepare 1111 Division-3 contests. But since we are planning only for the next D=7D=7 days and Chef cannot host more than 11 contest in a day, Chef cannot host more than 77 contests. Hence the third output is 77.

Code (Solution)

The code has been implemented in Java.

import java.util.*;

class Codechef
{
 public static void main (String[] args) throws java.lang.Exception
 {

  Scanner sc = new Scanner(System.in);
  int t = sc.nextInt();
  
  while(t-- > 0){
      int n = sc.nextInt();
      int k = sc.nextInt();
      int d = sc.nextInt();
      int count,sum =0;
      
      }
      
          if(sum < k){
              System.out.println("0");
             
          }
          else if(sum==k){
              System.out.println("1");
           
          }
          else{
              count = sum / k;
              if(count <= d)
              System.out.println(count);
              else
                  System.out.println(d);
          }
    
  }
 }
}

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References

https://www.codechef.com/JAN21C/problems/DIVTHREE